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Q1. - (Topic 2) 

What are two benefits of using a single OSPF area network design? (Choose two.) 

A. It is less CPU intensive for routers in the single area. 

B. It reduces the types of LSAs that are generated. 

C. It removes the need for virtual links. 

D. It increases LSA response times. 

E. It reduces the number of required OSPF neighbor adjacencies. 

Answer: B,C 

Explanation: 

OSPF uses a LSDB (link state database) and fills this with LSAs (link state advertisement). The link types are as follows: 

LSA Type 1:. Router LSA  

LSA Type 2:.. . . . . . . .  Network LSA  

LSA Type 3:. Summary LSA  

LSA Type 4:. Summary ASBR LSA  

LSA Type 5:. Autonomous system external LSA  

LSA Type 6:. Multicast OSPF LSA  

LSA Type 7:. Not-so-stubby area LSA  

LSA Type 8:. External attribute LSA for BGP  

If all routers are in the same area, then many of these LSA types (Summary ASBR LSA, external LSA, etc) will not be used and will not be generated by any router. 

All areas in an Open Shortest Path First (OSPF) autonomous system must be physically connected to the backbone area (Area 0). In some cases, where this is not possible, you can use a virtual link to connect to the backbone through a non-backbone area. You can also use virtual links to connect two parts of a partitioned backbone through a non-backbone area. The area through which you configure the virtual link, known as a transit area, must have full routing information. The transit area cannot be a stub area. Virtual links are not ideal and should really only be used for temporary network solutions or migrations. However, if all locations are in a single OSPF area this is not needed. 


Q2. - (Topic 1) 

Refer to the exhibit. 

At the end of an RSTP election process, which access layer switch port will assume the discarding role? 

A. Switch3, port fa0/1 

B. Switch3, port fa0/12 

C. Switch4, port fa0/11 

D. Switch4, port fa0/2 

E. Switch3, port Gi0/1 

F. Switch3, port Gi0/2 

Answer:

Explanation: 

In this question, we only care about the Access Layer switches (Switch3 & 4). Switch 3 has a lower bridge ID than Switch 4 (because the MAC of Switch3 is smaller than that of Switch4) so both ports of Switch3 will be in forwarding state. The alternative port will surely belong to Switch4. Switch4 will need to block one of its ports to avoid a bridging loop between the two switches. But how does Switch4 select its blocked port? Well, the answer is based on the BPDUs it receives from Switch3. A BPDU is superior than another if it has: 

1. A lower Root Bridge ID2. A lower path cost to the Root3. A lower Sending Bridge ID4. A lower Sending Port ID 

These four parameters are examined in order. In this specific case, all the BPDUs sent by Switch3 have the same Root Bridge ID, the same path cost to the Root and the same Sending Bridge ID. The only parameter left to select the best one is the Sending Port ID (Port ID = port priority + port index). In this case the port priorities are equal because they use the default value, so Switch4 will compare port index values, which are unique to each port on the switch, and because Fa0/12 is inferior to Fa0/1, Switch4 will select the port connected with Fa0/1 (of Switch3) as its root port and block the other port -> Port fa0/11 of Switch4 will be blocked (discarding role) 


Q3. - (Topic 2) 

Refer to the exhibit. 

C-router is to be used as a "router-on-a-stick" to route between the VLANs. All the interfaces have been properly configured and IP routing is operational. The hosts in the VLANs have been configured with the appropriate default gateway. What is true about this configuration? 

A. These commands need to be added to the configuration: C-router(config)# router eigrp 123 C-router(config-router)# network 172.19.0.0 

B. These commands need to be added to the configuration: C-router(config)# router ospf 1 C-router(config-router)# network 172.19.0.0 0.0.3.255 area 0 

C. These commands need to be added to the configuration: C-router(config)# router rip C-router(config-router)# network 172.19.0.0 

D. No further routing configuration is required. 

Answer:

Explanation: 

http://www.cisco.com/en/US/tech/tk389/tk815/technologies_configuration_example09186a 00800949fd.shtml https://learningnetwork.cisco.com/servlet/JiveServlet/download/5669-2461/Router%20on%20a%20Stick.pdf. 


Q4. - (Topic 2) 

Which type of EIGRP route entry describes a feasible successor? 

A. a backup route, stored in the routing table 

B. a primary route, stored in the routing table 

C. a backup route, stored in the topology table 

D. a primary route, stored in the topology table 

Answer:

Explanation: 

http://www.cisco.com/en/US/tech/tk365/technologies_tech_note09186a0080093f07.shtml 

Feasible Successors A destination entry is moved from the topology table to the routing table when there is a feasible successor. All minimum cost paths to the destination form a set. From this set, the neighbors that have an advertised metric less than the current routing table metric are considered feasible successors. Feasible successors are viewed by a router as neighbors that are downstream with respect to the destination. These neighbors and the associated metrics are placed in the forwarding table. When a neighbor changes the metric it has been advertising or a topology change occurs in the network, the set of feasible successors may have to be re-evaluated. However, this is not categorized as a route recomputation. Feasible successor is a route whose Advertised Distance (AD) is less than the Feasible Distance (FD) of the current best path. A feasible successor is a backup route, which is not stored in the routing table but, stored in the topology table. 


Q5. - (Topic 1) 

Refer to the exhibit. 

What commands must be configured on the 2950 switch and the router to allow communication between host 1 and host 2? (Choose two.) 

A. Router(config)# interface fastethernet 0/0 Router(config-if)# ip address 192.168.1.1 255.255.255.0 Router(config-if)# no shut down 

B. Router(config)# interface fastethernet 0/0 Router(config-if)# no shut down Router(config)# interface fastethernet 0/0.1 Router(config-subif)# encapsulation dot1q 10 Router(config-subif)# ip address 192.168.10.1 255.255.255.0 

Router(config)# interface fastethernet 0/0.2 Router(config-subif)# encapsulation dot1q 20 Router(config-subif)# ip address 192.168.20.1 255.255.255.0 

C. Router(config)# router eigrp 100 Router(config-router)# network 192.168.10.0 Router(config-router)# network 192.168.20.0 

D. Switch1(config)# vlan database Switch1(config-vlan)# vtp domain XYZ Switch1(config-vlan)# vtp server 

E. Switch1(config)# interface fastethernet 0/1 Switch1(config-if)# switchport mode trunk 

F. Switch1(config)# interface vlan 1 Switch1(config-if)# ip default-gateway 192.168.1.1 

Answer: B,E 

Explanation: 

The two answers B and E list all the commands needed to configure interVLAN routing. Please notice that Cisco switch 2950, 2960 only support dot1Q trunking so we don’t need to specify which trunking encapsulation to use in this case. For Cisco switches 3550 or above we have to use these commands instead: 

Switch3550(config-if)#switchport trunk encapsulation dot1q Switch3550(config-if)#switchport mode trunk 

References: http://www.cisco.com/en/US/tech/tk389/tk815/technologies_configuration_example09186a 00800949fd.shtml https://learningnetwork.cisco.com/servlet/JiveServlet/download/5669-2461/Router%20on%20a%20Stick.pdf. 


Q6. - (Topic 2) 

Refer to the exhibit. 

Assume that all of the router interfaces are operational and configured correctly. How will router R2 be affected by the configuration of R1 that is shown in the exhibit? 

A. Router R2 will not form a neighbor relationship with R1. 

B. Router R2 will obtain a full routing table, including a default route, from R1. 

C. R2 will obtain OSPF updates from R1, but will not obtain a default route from R1. 

D. R2 will not have a route for the directly connected serial network, but all other directly connected networks will be present, as well as the two Ethernet networks connected to R1. 

Answer:

Explanation: 

Open Shortest Path First http://en.wikipedia.org/wiki/Open_Shortest_Path_First 

The configuration of R1 shows "router ospf 1" however, the diagram also shows that both routers should be in the backbone OSPF Area of "0". When routers are in different OSPF areas they will not form a neighbor relationship. Neighbor relationships As a link state routing protocol, OSPF establishes and maintains neighbor relationships in order to exchange routing updates with other routers. The neighbor relationship table is called an adjacency database in OSPF. Provided that OSPF is configured correctly, OSPF forms neighbor relationships only with the routers directly connected to it. In order to form a neighbor relationship between two routers, the interfaces used to form the relationship must be in the same area. Generally an interface is only configured in a single area, however you can configure an interface to belong to multiple areas. In the second area, such an interface must be configured as a secondary interface. (A neighbor state simulation shows how neighbor state changes from Down to Full Adjacency progressively with exchanging Hello, DD, Request, Update, and Ack packets). 


Q7. - (Topic 2) 

Refer to the exhibit. 

Given the output from the “show ip eigrp topology” command, which router is the feasible successor? 

A) 

B) 

C) 

D) 

A. Exhibit A 

B. Exhibit B 

C. Exhibit C 

D. Exhibit D 

Answer:

Explanation: 

To be the feasible successor, the Advertised Distance (AD) of that route must be less than the Feasible Distance (FD) of the successor. From the output of the “show ip eigrp topology 

10.0.0.5 255.255.255.255 we learn that the FD of the successor is 41152000. Now we will mention about the answers, in the “Composite metric is (…/…)” statement the first parameter is the FD while the second parameter is the AD of that route. So we need to find out which route has the second parameter (AD) less than 41152000 -> only answer B satisfies this requirement with an AD of 128256. 

Reference: http://networklessons.com/eigrp/eigrp-neighbor-and-topology-table-explained/ 


Q8. - (Topic 3) 

Refer to the exhibit. 

What is the meaning of the term dynamic as displayed in the output of the show frame-relay map command shown? 

A. The Serial0/0 interface is passing traffic. 

B. The DLCI 100 was dynamically allocated by the router 

C. The Serial0/0 interface acquired the IP address of 172.16.3.1 from a DHCP server 

D. The DLCI 100 will be dynamically changed as required to adapt to changes in the Frame Relay cloud 

E. The mapping between DLCI 100 and the end station IP address 172.16.3.1 was learned through Inverse ARP 

Answer:

Explanation: 

The term dynamic indicates that the DLCI number and the remote router IP address 

172.16.3.1 are learned via the Inverse ARP process. 

Inverse ARP is a technique by which dynamic mappings are constructed in a network, allowing a device such as a router to locate the logical network address and associate it with a permanent virtual circuit (PVC).